Решите систему уравнений: 6x+3=8x-3(2y-4); 2(2x-3y)-4x=2y-8.

\[\left\{ \begin{matrix} 6x + 3 = 8x - 3 \cdot (2y - 4)\text{\ \ } \\ 2 \cdot (2x - 3y) - 4x = 2y - 8 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 6x + 3 = 8x - 6y + 12\ \ \\ 4x - 6y - 4x - 2y = - 8 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 2x - 6y = - 9 \\ - 8y = - 8\ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix} y = 1\ \ \ \ \ \ \ \ \ \ \ \ \ \\ 2x = - 9 + 6 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 1\ \ \\ 2x = 3 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 1\ \ \ \\ x = 1,5 \\ \end{matrix} \right.\ \]

\[Ответ:(1,5;1).\]