Решите систему уравнений: (p+3)/4-(q-2)/6=1; (p-1)/8+(q+1)/6=2.

\[\left\{ \begin{matrix} \frac{p + 3}{4} - \frac{q - 2}{6} = 1\ \ \ \ | \cdot 12 \\ \frac{p - 1}{8} + \frac{q + 1}{6} = 2\ \ \ | \cdot 24 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 3p + 9 - 2q + 4 = 12 \\ 3p - 3 + 4q + 4 = 48 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 3p - 2q = - 1 \\ 3p + 4q = 47 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 6q = - 48 \\ p = \frac{47 - 4q}{3} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} q = 8 \\ p = 5 \\ \end{matrix} \right.\ \]

\[Ответ:(5;8).\]