Решите систему уравнений: x=y-2; xy-y=10.

\[y^{2} - 2y - y - 10 = 0\]

\[y^{2} - 3y - 10 = 0\]

\[y_{1} + y_{2} = 3;\ \ \ y_{1} \cdot y_{2} = - 10\]

\[y_{1} = 5;\ \ \ \ y_{2} = - 2.\]

\[\left\{ \begin{matrix} y = 5 \\ x = 3 \\ \end{matrix} \right.\ \ \ \ \ или\ \ \ \ \ \left\{ \begin{matrix} y = - 2 \\ x = - 4 \\ \end{matrix} \right.\ \]

\[Ответ:(3;5);\ \ ( - 4; - 2).\]