Решите систему уравнений: (x-2)(y-1)=30; 2x-y=10.

\[(x - 2)(2x - 11) = 30\]

\[2x^{2} - 4x - 11x + 22 - 30 = 0\]

\[2x^{2} - 15x - 8 = 0\]

\[D = 225 + 64 = 289\]

\[x_{1} = \frac{15 + 17}{4} = 8;\ \ \]

\[\ x_{2} = \frac{15 - 17}{4} = - \frac{2}{4} = - 0,5.\]

\[\left\{ \begin{matrix} x = 8 \\ y = 6 \\ \end{matrix} \right.\ \ \ \ \ \ или\ \ \ \ \left\{ \begin{matrix} x = - 0,5 \\ y = - 11\ \\ \end{matrix} \right.\ \]

\[Ответ:(8;6);\ \ ( - 0,5; - 11).\]