Решите систему уравнений: x-6y=20; 4x+2y=2.

\[\left\{ \begin{matrix} x - 6y = 20\ \ \ \ | \cdot 2 \\ 4x + 2y = 2\ \ \ |\ :2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2x - 12y = 40 \\ 2x + y = 1\ \ \ \ \ \ \ \\ \end{matrix} \right.\ ( - )\]

\[- 13y = 39\]

\[y = - 3.\]

\[\left\{ \begin{matrix} x = 20 + 6y \\ y = - 3\ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\left\{ \begin{matrix} y = - 3\ \ \ \ \ \ \ \ \ \ \\ x = 20 - 18 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = - 3 \\ x = 2\ \ \ \\ \end{matrix} \right.\ \]

\[Ответ:(2;\ - 3).\]