Решите систему уравнений: y+x=6; 8/x+2/y=3.

\[8 \bullet (6 - x) + 2x = 3x(6 - x)\]

\[48 - 8x + 2x = 18x - 3x^{2}\]

\[48 - 6x - 18x + 3x^{2} = 0\]

\[3x^{2} - 24x + 48 = 0\ \ \ \ \ \ \ |\ :3\]

\[x^{2} - 8x + 16 = 0\]

\[(x - 4)^{2} = 0\]

\[x - 4 = 0\]

\[x = 4\]

\[x = 4 \Longrightarrow y = 6 - 4 = 2.\]

\[Ответ:(4;2).\]