Решите уравнение: 1/3*x+1/4*x+1/8*x=34/45.

\[\frac{1^{\backslash 8}}{3}x + \frac{1^{\backslash 6}}{4}x + \frac{1^{\backslash 3}}{8}x = \frac{34}{45}\]

\[\frac{8 + 6 + 3}{24}x = \frac{34}{45}\]

\[\frac{17}{24}x = \frac{34}{45}\]

\[x = \frac{34 \cdot 24}{45 \cdot 17} = \frac{16}{15}\]

\[x = 1\frac{1}{15}.\]