\[2x^{2} - 7x + 5 = 0\]
\[D = 49 - 40 = 9\]
\[x_{1} = \frac{7 + 3}{4} = \frac{10}{4} = 2,5;\]
\[x_{2} = \frac{7 - 3}{4} = 1.\]
\[Ответ:x = 1;x = 2,5.\]