Решите уравнение 2x^3-32x=0.

\[2x^{3} - 32x = 0\]

\[2x\left( x^{2} - 16 \right) = 0\]

\[2x(x - 4)(x + 4) = 0\]

\[2x = 0;\ \ \ \ x - 4 = 0;\ \ \ x + 4 = 0\]

\[x = 0\ \ \ \ \ \ \ \ x = 4\ \ \ \ \ \ \ \ \ \ \ \ \ x = - 4\]

\[Ответ:x = 0;\ \ x = \pm 4.\]