Решите уравнение: 3*(x-2)(x+4)=2x^2+x.

\[3 \cdot (x - 2)(x + 4) = 2x^{2} + x\]

\[3 \cdot \left( x^{2} - 2x + 4x - 8 \right) = 2x^{2} + x\]

\[3x^{2} + 6x - 24 - 2x^{2} - x = 0\]

\[x^{2} + 5x - 24 = 0\]

\[x_{1} + x_{2} = - 5;\ \ x_{1} \cdot x_{2} = - 24\]

\[x_{1} = - 8;\ \ x_{2} = 3.\]

\[Ответ:x = - 8;\ \ x = 3.\]