Решите уравнение: 3x^2+8x-3=0;

\[\ 3x² + 8x - 3 = 0\]

\[D = b^{2} - 4ac = 64 - 4 \cdot 3 \cdot ( - 3) =\]

\[= 64 + 36 = 100\]

\[x_{1} = \frac{- 8 + 10}{6} = \frac{2}{6} = \frac{1}{3}\]

\[x_{2} = \frac{- 8 - 10}{6} = - \frac{18}{6} = - 3\]

\[Ответ:x = \frac{1}{3}\ \ и\ \ x = - 3.\]