Решите уравнение: 3x^2-2x-8=0.

\[3x^{2} - 2x - 8 = 0\]

\[D_{1} = 1 + 24 = 25\]

\[x_{1} = \frac{1 + 5}{3} = 2;\]

\[x_{2} = \frac{1 - 5}{3} = - \frac{4}{3} = - 1\frac{1}{3}.\]

\[Ответ:x = - 1\frac{1}{3};x = 2.\]