Решите уравнение 3x^3-12x=0.

\[3x^{3} - 12x = 0\]

\[3x\left( x^{2} - 4 \right) = 0\]

\[3x(x - 2)(x + 2) = 0\]

\[3x = 0;\ \ \ \ x - 2 = 0;\ \ \ x + 2 = 0\]

\[x = 0\ \ \ \ \ \ \ \ x = 2\ \ \ \ \ \ \ \ \ \ \ \ \ x = - 2\]

\[Ответ:x = 0;\ \ x = \pm 2.\]