Решите уравнение (3x−5)(2x+7)=(3x+1)(2x−3)+4x.

\[(3x - 5)(2x + 7) = (3x + 1)(2x - 3) + 4x\]

\[6x^{2} - 10x + 21x - 35 = 6x^{2} + 2x - 9x - 3 + 4x\]

\[11x + 3x = - 3 + 35\]

\[14x = 32\]

\[x = \frac{32}{14} = \frac{16}{7}\]

\[x = 2\frac{2}{7}.\]