Решите уравнение: 3x-2*корень из x-8=0.

\[3x - 2\sqrt{x} - 8 = 0\]

\[\sqrt{x} = t \geq 0:\]

\[3t^{2} - 2t - 8 = 0\]

\[D_{1} = 1 + 24 = 25\]

\[t_{1} = \frac{1 + 5}{3} = 2;\]

\[t_{2} = \frac{1 - 5}{3} = - \frac{4}{3} < 0.\]

\[\sqrt{x} = 2\]

\[x = 4.\]

\[Ответ:x = 4.\]