Решите уравнение: 49x^2-9=0.

\[49x² - 9 = 0\]

\[(7x - 3)(7x + 3) = 0\]

\[7x - 3 = 0,\ \ 7x + 3 = 0\]

\[7x = 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 7x = - 3\]

\[x = \frac{3}{7}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - \frac{3}{7}\]

\[Ответ:\ x = - \frac{3}{7};x = \ \frac{3}{7}.\]