Решите уравнение: (5x+1)/6-(x+3)/4=3.

\[\frac{5x + 1}{6} - \frac{x + 3}{4} = 3\ \ \ \ \ \ \ | \cdot 12\]

\[2 \cdot (5x + 1) - 3 \cdot (x + 3) = 36\]

\[10x + 2 - 3x - 9 = 36\]

\[7x = 36 + 7\]

\[7x = 43\]

\[x = 6\frac{1}{7}.\]