Решите уравнение: 5x^2-35=0.

\[5x² - 35 = 0\]

\[5 \cdot \left( x^{2} - 7 \right) = 0\]

\[5 \cdot \left( x - \sqrt{7} \right)\left( x + \sqrt{7} \right) = 0\]

\[x - \sqrt{7} = 0\ \ \ \ \ \ \ \ \ x + \sqrt{7} = 0\]

\[x = \sqrt{7}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - \sqrt{7}\]

\[Ответ:x = \sqrt{7};\ x = - \sqrt{7}.\]