Решите уравнение (5x−1)(x+2)+3(x−4)(x+4)=2(2x+3)^2−8.

\[(5x - 1)(x + 2) + 3(x - 4)(x + 4) = 2(2x + 3)^{2} - 8\]

\[5x^{2} - x + 10x - 2 + 3x^{2} - 48 = 2 \cdot \left( 4x^{2} + 12x + 9 \right) - 8\]

\[8x^{2} + 9x - 50 = 8x^{2} + 24x + 18 - 8\]

\[9x - 24x = 10 + 50\]

\[- 15x = 60\]

\[x = - 4.\]

\[Ответ:x = - 4.\]