Решите уравнение 64x^3-16x^2+x=0.

\[64x^{3} - 16x^{2} + x = 0\]

\[x\left( 64x^{2} - 16x + 1 \right) = 0\]

\[x(8x - 1)^{2} = 0\]

\[x = 0;\ \ \ \ \ \ \ 8x - 1 = 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8x = 1\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = \frac{1}{8}\]

\[Ответ:x = 0;\ \ x = \frac{1}{8}.\]