Решите уравнение 7x^2-22x+3=0.

\[7x² - 22x + 3 = 0\]

\[D = 484 - 84 = 400\]

\[x_{1} = \frac{22 + 20}{14} = \frac{42}{14} = 3;\ \ \]

\[x_{2} = \frac{22 - 20}{14} = \frac{2}{14} = \frac{1}{7}.\]

\[Ответ:x = 3;x = \frac{1}{7}.\]