Решите уравнение: 7y^2-4y-3=0.

\[7y² - 4y - 3 = 0\]

\[D = ( - 4)^{2} - 4 \cdot 7 \cdot ( - 3) =\]

\[= 16 + 84 = 100\]

\[y_{1} = \frac{4 + \sqrt{100}}{2 \cdot 7} = \frac{4 + 10}{14} =\]

\[= \frac{14}{14} = 1\]

\[y_{2} = \frac{4 - \sqrt{100}}{2 \cdot 7} = \frac{4 - 10}{14} =\]

\[= - \frac{6}{14} = - \frac{3}{7}\]

\[Ответ:y = 1;\ y - \frac{3}{7}.\]