Решите уравнение: (8x^2-x)/3x=0

\[\ \frac{8x^{2} - x}{3x} = 0\ \ \ \ \ \ \ \ \ \ \ \ \ ОДЗ:\ x \neq 0\ \ \ \]

\[\frac{x(8x - 1)}{3x} = 0\]

\[8x - 1 = 0\]

\[8x = 1\]

\[x = \frac{1}{8}\]

\[Ответ:\ \ \ \ x = \frac{1}{8}.\]

\[x < 0;\ \ y < 0\]

\[\ x^{3}y^{8} < 0\]

\[x³ < 0;\ \ \ y^{8} > 0\]