Решите уравнение методом замены переменной: x^2/(3x+1)^2-6x/(3x+1)+5=0.

\[\frac{x^{2}}{(3x + 1)^{2}} - \frac{6x}{3x + 1} + 5 = 0\ \ \]

\[Пусть\ t = \frac{x}{3x + 1};\ x \neq - \frac{1}{3}:\]

\[t² - 6t + 5 = 0\]

\[t_{1} + t_{2} = 6;\ \ t_{1} \cdot t_{2} = 5\]

\[t_{1} = 5,\ \ t_{2} = 1.\]