Решите уравнение: n(12-n)-5=4n-n(10+(n-3)).

\[n(12 - n) - 5 =\]

\[= 4n - n(10 + (n - 3))\]

\[12n - n^{2} - 5 =\]

\[= 4n - 10n - n(n - 3)\]

\[12n + 6n - n^{2} - 5 = - n^{2} + 3n\]

\[18n - n^{2} + n^{2} - 3n = 5\]

\[15n = 5\]

\[n = \frac{5}{15}\]

\[n = \frac{1}{3}.\]