Решите уравнение: x+1=(x-3)^2/2+(x(x+2))/4+(x-1)/2.

\[3x^{2} - 8x - 4x + 16 - 4 = 0\]

\[3x^{2} - 12x + 12 = 0\ \ \ \ \ |\ :3\]

\[x^{2} - 4x + 4 = 0\]

\[(x - 2)^{2} = 0\]

\[x = 2.\]

\[Ответ:x = 2.\]