Решите уравнение: x^2-5x+3-(3x^2-5x-7)/3=1/3.

\[x^{2} - 5x + 3 - \frac{3x^{2} - 5x - 7}{3} = \frac{1}{3}\ \ \ | \cdot 3\]

\[3x^{2} - 15x + 9 - 3x^{2} + 5x + 7 = 1\]

\[- 10x = 1 - 16\]

\[- 10x = - 15\]

\[x = \frac{15}{10}\]

\[x = 1,5.\ \]