Решите уравнение: y^3-2y^2=y-2.

\[y^{3} - 2y^{2} = y - 2\]

\[y^{2}(y - 2) - (y - 2) = 0\ \]

\[(y - 2)\left( y^{2} - 1 \right) = 0\]

\[(y - 2)(y - 1)(y + 1) = 0\]

\[y = 2;\ \ y = 1;\ \ y = - 1.\]

\[Ответ:\ \ y = \pm 1;\ \ y = 2.\]