Сократите дробь: (36a^2-12a+1)/(6a^2+11a-2).

Ответ:

\[6a^{2} + 11a - 2 = 0\]

\[a_{1} + a_{2} = - \frac{11}{6}\]

\[a_{1} \cdot a_{2} = - \frac{1}{3}\]

\[\Longrightarrow a_{1} = \frac{1}{6};\ \ a_{2} = - 2.\]

\[6a^{2} + 11a - 2 =\]

\[= 6 \cdot \left( a - \frac{1}{6} \right)(a + 2) =\]

\[= (6a - 1)(a + 2).\]