\[b < 0:\]
\[- 5b^{2}\sqrt{\frac{4}{b^{2}}} = \frac{- 5b^{2} \cdot 2}{|b|} = \frac{- 10b^{2}}{- b} = 10b.\]
\[4,1^{2} = 16,81;\]
\[4,2^{2} = 17,64;\]
\[4,\ 1 < \sqrt{17} < 4,2.\]
\[\frac{8}{\sqrt{a} - 4}\]
\[\sqrt{a} - 4 \neq 0\]
\[\sqrt{a} \neq 4\]
\[a \neq 16\]
\[Выражение\ имеет\ смысл\ при\ \ a \geq 0\ \ и\ \]
\[a \neq 16.\]
\[\frac{1}{2}\sqrt{196} + 1,5\sqrt{0,36} = \frac{1}{2} \cdot 14 + 1,5 \cdot 0,6 =\]
\[= 7 + 0,9 = 7,9\]