Упростите выражение: (16-7x)/(x-4)^2 -(x-x^2)/(4-x)^2.

\[\frac{16 - 7x}{(x - 4)^{2}} - \frac{x - x^{2}}{(4 - x)^{2}} =\]

\[= \frac{16 - 7x}{(x - 4)^{2}} - \frac{x - x^{2}}{(x - 4)^{2}} =\]

\[= \frac{16 - 7x - x + x^{2}}{(x - 4)^{2}} =\]

\[= \frac{x² - 8x + 16}{(x - 4)²} = \frac{(x - 4)²}{(x - 4)²} = 1\]