Упростите выражение: (3y^2-10y+8)/(4y^2-36)*(y-3)/(y-2)+(0,25-y)/(y+3).

\[= \frac{3y - 4}{4 \cdot (y + 3)} + \frac{0,25 - y^{\backslash 4}}{y + 3} =\]

\[= \frac{3y - 4 + 1 - 4y}{4 \cdot (y + 3)} =\]

\[= \frac{- y - 3}{4 \cdot (y + 3)} = \frac{- (y + 3)}{4 \cdot (y + 3)} =\]

\[= - \frac{1}{4}.\]

\[Дополнительные\ вычисления:\]

\[3y^{2} - 10y + 8 = 0\]

\[D_{1} = 25 - 24 = 1\]

\[y_{1} = \frac{5 + 1}{3} = 2;\ \ \ \]

\[y_{2} = \frac{5 - 1}{3} = \frac{4}{3}.\]

\[3y^{2} - 10y + 8 =\]

\[= 3 \cdot (y - 2)\left( y - \frac{4}{3} \right) =\]

\[= (y - 2)(3y - 4).\]