\[\frac{6^{- 3} \bullet 2^{- 4}}{18^{- 2}} = \frac{6^{- 3} \bullet 2^{- 4}}{6^{- 2} \bullet 3^{- 2}} = \frac{3^{2}}{6 \bullet 2^{4}} =\]
\[= \frac{3 \bullet 3}{3 \bullet 2 \bullet 2^{4}} = \frac{3}{2^{5}} = \frac{3}{32}\]