\[32^{- 2}{\cdot 4}^{4} = \left( 2^{5} \right)^{- 2} \cdot \left( 2^{2} \right)^{4} =\]
\[= 2^{- 10} \cdot 2^{8} = 2^{- 2} = \frac{1}{4}\]