Вычислите: 5^-3; (-4)^-2; (2/3)^-1; (0,35)^0.

Ответ:

\[5^{- 3} = \frac{1}{5^{3}} = \frac{1}{125};\text{\ \ \ \ \ \ }\]

\[( - 4)^{- 2} = \frac{1}{( - 4)^{2}} = \frac{1}{16}\]

\[\left( \frac{2}{3} \right)^{- 1} = \frac{3}{2} = 1,5;\text{\ \ \ \ }\]

\[(0,34)^{0} = 1.\]