Вычислите: (9^-1*27^(2/5))/3^(1/5).

Ответ:

\[\frac{9^{- 1} \cdot 27^{\frac{2}{5}}}{3^{\frac{1}{5}}} = \frac{\left( 3^{2} \right)^{- 1} \cdot \left( 3^{3} \right)^{\frac{2}{5}}}{3^{\frac{1}{5}}} = \frac{3^{- 2} \cdot 3^{\frac{6}{5}}}{3^{\frac{1}{5}}} =\]

\[= 3^{- 2 + \frac{6}{5} - \frac{1}{5}} = 3^{- 1} = \frac{1}{3}.\]