Выполните действия: 2/(a^2-9)-1/(a^2+3a).

Ответ:

\[\frac{2}{a^{2} - 9} - \frac{1}{a^{2} + 3a} =\]

\[= \frac{2^{\backslash a}}{(a - 3)(a + 3)} - \frac{1^{\backslash a - 3}}{a(a + 3)} =\]

\[= \frac{2a - a + 3}{a(a - 3)(a + 3)} =\]

\[= \frac{a + 3}{a(a - 3)(a + 3)} = \frac{1}{a^{2} - 3a}.\]