\[6\frac{7^{\backslash 3}}{32} - 2\frac{11^{\backslash 2}}{48} = 6\frac{21}{96} - 2\frac{22}{96} =\]
\[= 5\frac{117}{96} - 2\frac{22}{96} = 3\frac{95}{96}\]