\[\frac{y - 8^{\backslash y}}{2y} - \frac{3 - 4y^{\backslash 2}}{y^{2}} = \frac{y^{2} - 8y - 6 + 8y}{2y^{2}} =\]
\[= \frac{y^{2} - 6}{2y^{2}}\]