\[\frac{(y - 8)}{2y} - \frac{3 - 4y}{y^{2}} =\]
\[= \frac{y(y - 8) - 2(3 - 4y)}{2y^{2}} =\]
\[= \frac{y^{2} - 8y - 6 + 8y}{2y^{2}} = \frac{y^{2} - 6}{2y^{2}}.\]