\[\frac{1}{4};\ \frac{1}{2};\ \ 1;\ \ 2;\ \ 4;\ldots \Longrightarrow q = 2\]
\[b_{n} = b_{1} \cdot q^{n - 1} = \frac{1}{4} \cdot 2^{n - 1} =\]
\[= \frac{1}{4} \cdot 2^{n} \cdot \frac{1}{2} = \frac{1}{8} \cdot 2^{n} \Longrightarrow\]
\[= b_{n} = \frac{1}{8} \cdot 2^{n}.\]