\[\frac{1}{9};\ - \frac{1}{3};\ \ 1;\ - 3;\ \ 9;\ldots \Longrightarrow q = - 3.\]
\[b_{n} = b_{1} \cdot q^{n - 1} = \frac{1}{9} \cdot ( - 3)^{n - 1} =\]
\[= \frac{1}{9} \cdot ( - 3)^{n} \cdot \left( - \frac{1}{3} \right) =\]
\[= - \frac{1}{27} \cdot ( - 3)^{n} \Longrightarrow\]
\[\Longrightarrow b_{n} = - \frac{1}{27} \cdot ( - 3)^{n}\]