\[\left\{ \begin{matrix} x^{2} - 4y = - 28\ \ \ \ \ (1) \\ y^{2} + 8x = 8\ \ \ \ \ \ \ \ \ \ \ (2) \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} (x + 4)^{2} + (y - 2)^{2} = 0 \\ y^{2} + 8x = 8\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]
\[x = - 4;\ \ \ y = 2:\]
\[2^{2} + 8 \cdot ( - 4) = 8\]
\[4 - 32 = 8\]
\[- 28 \neq 8 \Longrightarrow ( - 4;2) \Longrightarrow\]
\[\Longrightarrow не\ решение.\]
\[Нет\ решений \Longrightarrow ч.т.д.\]