Найдите корни уравнения: 1/(2x-1)-(13x-4)/(4x^2-4x+1)=4.

\[\frac{1}{2x - 1} - \frac{13x - 4}{4x^{2} - 4x + 1} = 4\]

\[ОДЗ:\ \ 2x - 1 \neq 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \Longrightarrow x \neq 0,5\]

\[\frac{1}{2x - 1} - \frac{13x - 4}{(2x - 1)^{2}} = 4\]

\[\frac{2x - 1 - (13x - 4)}{(2x - 1)^{2}} = 4\]

\[2x - 1 - 13x + 4 =\]

\[= 4 \cdot (4x^{2} - 4x + 1)\]

\[3 - 11x = 16x^{2} - 16x + 4\]

\[16x^{2} - 5x + 1 = 0\]

\[D = b^{2} - 4ac =\]

\[= 25 - 4 \cdot 1 \cdot 16 = 25 - 64 < 0\]

\[Ответ:нет\ корней.\]