Постройте график функции: y=(x^2-3x-10)/(x+2).

Question

Вопрос:

Ответ:

Accepted Answer

\[y = \frac{x^{2} - 3x - 10}{x + 2} =\]

\[x^{2} - 3x - 10 = 0\]

\[x_{1} + x_{2} = 3;\ \ x_{1} \cdot x_{2} = - 10\]

\[\Longrightarrow x_{1} = 5;\ \ x_{2} = - 2\]

\[x^{2} - 3x - 10 = (x - 5)(x + 2)\]

\[y = x - 5;x \neq - 2.\]

\[x\]	\[0\]	\[2\]
\[y\]	\[- 5\]	\[- 3\]