\[x^{2} + (a + 5)x + 1 = 0\]
\[D = a^{2} + 10a + 25 - 4 =\]
\[= a^{2} + 10a + 21 < 0\]
\[a^{2} + 10a + 21 > 0\]
\[a_{1} + a_{2} = - 10,\ \ a_{1} \cdot a_{2} = 21\]
\[a_{1} = - 7,\ \ a_{2} = - 3\]
\[(a + 7)(a + 3) > 0\]
\[a < - 7;\ \ \ a > - 3.\]
\[Ответ:( - \infty;\ - 7) \cup ( - 3; + \infty).\]