Решите неравенство: -3x^2+4x+4>0.

\[- 3x^{2} + 4x + 4 > 0\]

\[- 3x^{2} + 4x + 4 = 0\]

\[D = 16 + 48 = 64\]

\[x_{1} = \frac{- 4 + 8}{- 6} = - \frac{2}{3}\]

\[x_{2} = \frac{- 4 - 8}{- 6} = 2\]

\[Ответ:x \in \left( - \frac{2}{3};2 \right)\text{.\ }\]