Решите неравенство: 2x^2-x-15>0.

Ответ:

\[2x^{2} - x - 15 > 0\]

\[D = 1 + 120 = 121\]

\[x_{1} = \frac{1 + 11}{4} = 3;\]

\[x_{2} = \frac{1 - 11}{4} = - \frac{10}{4} = - 2,5.\]

\[(x + 2,5)(x - 3) > 0\]

\[x < - 2,5;\ \ x > 3.\]

\[Ответ:x < - 2,5;x > 3.\]