\[x^{2} - 5x - 36 > 0\]
\[x_{1} + x_{2} = 5;x_{1} \cdot x_{2} = - 36\]
\[x_{1} = 9;\ \ x_{2} = - 4.\]
\[(x + 4)(x - 9) > 0\]
\[x < - 4;\ \ x > 9.\]
\[Ответ:x < - 4;x > 9.\]