Решите систему неравенств: 2x^2-3x-9<=0; 2x-7>=0.

\[\left\{ \begin{matrix} 2x² - 3x - 9 \leq 0\ \ (1) \\ 2x - 7 \geq 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ (2) \\ \end{matrix} \right.\ \]

\[(1)\ D = 9 + 72 = 81\]

\[x_{1} = \frac{3 + 9}{4} = 3\]

\[x_{2} = \frac{3 - 9}{4} = - 1,5\]

\[(2)\ \ \ x \geq 3,5\]

\[Ответ:\ \varnothing.\]